2(u-3)-5=-3(-7u+1)-3u

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Solution for 2(u-3)-5=-3(-7u+1)-3u equation: 



2(u-3)-5=-3(-7u+1)-3u

We move all terms to the left:

2(u-3)-5-(-3(-7u+1)-3u)=0

We multiply parentheses

2u-(-3(-7u+1)-3u)-6-5=0



We calculate terms in parentheses: -(-3(-7u+1)-3u), so:

-3(-7u+1)-3u

We add all the numbers together, and all the variables

-3u-3(-7u+1)

We multiply parentheses

-3u+21u-3

We add all the numbers together, and all the variables

18u-3

Back to the equation:

-(18u-3)



We add all the numbers together, and all the variables

2u-(18u-3)-11=0

We get rid of parentheses

2u-18u+3-11=0

We add all the numbers together, and all the variables

-16u-8=0

We move all terms containing u to the left, all other terms to the right

-16u=8

u=8/-16

u=-1/2

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