2(u-3)=3(u-4)-(u-6)

Solution for 2(u-3)=3(u-4)-(u-6) equation:

Simplifying
2(u + -3) = 3(u + -4) + -1(u + -6)

Reorder the terms:
2(-3 + u) = 3(u + -4) + -1(u + -6)
(-3 * 2 + u * 2) = 3(u + -4) + -1(u + -6)
(-6 + 2u) = 3(u + -4) + -1(u + -6)

Reorder the terms:
-6 + 2u = 3(-4 + u) + -1(u + -6)
-6 + 2u = (-4 * 3 + u * 3) + -1(u + -6)
-6 + 2u = (-12 + 3u) + -1(u + -6)

Reorder the terms:
-6 + 2u = -12 + 3u + -1(-6 + u)
-6 + 2u = -12 + 3u + (-6 * -1 + u * -1)
-6 + 2u = -12 + 3u + (6 + -1u)

Reorder the terms:
-6 + 2u = -12 + 6 + 3u + -1u

Combine like terms: -12 + 6 = -6
-6 + 2u = -6 + 3u + -1u

Combine like terms: 3u + -1u = 2u
-6 + 2u = -6 + 2u

Add '6' to each side of the equation.
-6 + 6 + 2u = -6 + 6 + 2u

Combine like terms: -6 + 6 = 0
0 + 2u = -6 + 6 + 2u
2u = -6 + 6 + 2u

Combine like terms: -6 + 6 = 0
2u = 0 + 2u
2u = 2u

Add '-2u' to each side of the equation.
2u + -2u = 2u + -2u

Combine like terms: 2u + -2u = 0
0 = 2u + -2u

Combine like terms: 2u + -2u = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.