2(u-3)=3u+5-2(-4u-2)

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Solution for 2(u-3)=3u+5-2(-4u-2) equation: 



2(u-3)=3u+5-2(-4u-2)

We move all terms to the left:

2(u-3)-(3u+5-2(-4u-2))=0

We multiply parentheses

2u-(3u+5-2(-4u-2))-6=0



We calculate terms in parentheses: -(3u+5-2(-4u-2)), so:

3u+5-2(-4u-2)

determiningTheFunctionDomain
3u-2(-4u-2)+5

We multiply parentheses

3u+8u+4+5

We add all the numbers together, and all the variables

11u+9

Back to the equation:

-(11u+9)



We get rid of parentheses

2u-11u-9-6=0

We add all the numbers together, and all the variables

-9u-15=0

We move all terms containing u to the left, all other terms to the right

-9u=15

u=15/-9

u=-1+2/3

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