2(u-4)+4u=22

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Solution for 2(u-4)+4u=22 equation: 



2(u-4)+4u=22

We move all terms to the left:

2(u-4)+4u-(22)=0

We add all the numbers together, and all the variables

4u+2(u-4)-22=0

We multiply parentheses

4u+2u-8-22=0

We add all the numbers together, and all the variables

6u-30=0

We move all terms containing u to the left, all other terms to the right

6u=30

u=30/6

u=5

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