2(u-4)-6=-2(-9u+2)-8u

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Solution for 2(u-4)-6=-2(-9u+2)-8u equation: 



2(u-4)-6=-2(-9u+2)-8u

We move all terms to the left:

2(u-4)-6-(-2(-9u+2)-8u)=0

We multiply parentheses

2u-(-2(-9u+2)-8u)-8-6=0



We calculate terms in parentheses: -(-2(-9u+2)-8u), so:

-2(-9u+2)-8u

We add all the numbers together, and all the variables

-8u-2(-9u+2)

We multiply parentheses

-8u+18u-4

We add all the numbers together, and all the variables

10u-4

Back to the equation:

-(10u-4)



We add all the numbers together, and all the variables

2u-(10u-4)-14=0

We get rid of parentheses

2u-10u+4-14=0

We add all the numbers together, and all the variables

-8u-10=0

We move all terms containing u to the left, all other terms to the right

-8u=10

u=10/-8

u=-1+1/4

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