2(u-4)-6=-2(9u+2)-8u

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Solution for 2(u-4)-6=-2(9u+2)-8u equation: 



2(u-4)-6=-2(9u+2)-8u

We move all terms to the left:

2(u-4)-6-(-2(9u+2)-8u)=0

We multiply parentheses

2u-(-2(9u+2)-8u)-8-6=0



We calculate terms in parentheses: -(-2(9u+2)-8u), so:

-2(9u+2)-8u

We add all the numbers together, and all the variables

-8u-2(9u+2)

We multiply parentheses

-8u-18u-4

We add all the numbers together, and all the variables

-26u-4

Back to the equation:

-(-26u-4)



We add all the numbers together, and all the variables

2u-(-26u-4)-14=0

We get rid of parentheses

2u+26u+4-14=0

We add all the numbers together, and all the variables

28u-10=0

We move all terms containing u to the left, all other terms to the right

28u=10

u=10/28

u=5/14

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