2(u-4)-6=-5(-2u+2)-2u

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Solution for 2(u-4)-6=-5(-2u+2)-2u equation: 



2(u-4)-6=-5(-2u+2)-2u

We move all terms to the left:

2(u-4)-6-(-5(-2u+2)-2u)=0

We multiply parentheses

2u-(-5(-2u+2)-2u)-8-6=0



We calculate terms in parentheses: -(-5(-2u+2)-2u), so:

-5(-2u+2)-2u

We add all the numbers together, and all the variables

-2u-5(-2u+2)

We multiply parentheses

-2u+10u-10

We add all the numbers together, and all the variables

8u-10

Back to the equation:

-(8u-10)



We add all the numbers together, and all the variables

2u-(8u-10)-14=0

We get rid of parentheses

2u-8u+10-14=0

We add all the numbers together, and all the variables

-6u-4=0

We move all terms containing u to the left, all other terms to the right

-6u=4

u=4/-6

u=-2/3

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