2(u-4)-6=-5(-2u+2)-2u

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Solution for 2(u-4)-6=-5(-2u+2)-2u equation:



2(u-4)-6=-5(-2u+2)-2u
We move all terms to the left:
2(u-4)-6-(-5(-2u+2)-2u)=0
We multiply parentheses
2u-(-5(-2u+2)-2u)-8-6=0
We calculate terms in parentheses: -(-5(-2u+2)-2u), so:
-5(-2u+2)-2u
We add all the numbers together, and all the variables
-2u-5(-2u+2)
We multiply parentheses
-2u+10u-10
We add all the numbers together, and all the variables
8u-10
Back to the equation:
-(8u-10)
We add all the numbers together, and all the variables
2u-(8u-10)-14=0
We get rid of parentheses
2u-8u+10-14=0
We add all the numbers together, and all the variables
-6u-4=0
We move all terms containing u to the left, all other terms to the right
-6u=4
u=4/-6
u=-2/3

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