2(u-4)=2u+6-2(-4u-2)

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Solution for 2(u-4)=2u+6-2(-4u-2) equation: 



2(u-4)=2u+6-2(-4u-2)

We move all terms to the left:

2(u-4)-(2u+6-2(-4u-2))=0

We multiply parentheses

2u-(2u+6-2(-4u-2))-8=0



We calculate terms in parentheses: -(2u+6-2(-4u-2)), so:

2u+6-2(-4u-2)

determiningTheFunctionDomain
2u-2(-4u-2)+6

We multiply parentheses

2u+8u+4+6

We add all the numbers together, and all the variables

10u+10

Back to the equation:

-(10u+10)



We get rid of parentheses

2u-10u-10-8=0

We add all the numbers together, and all the variables

-8u-18=0

We move all terms containing u to the left, all other terms to the right

-8u=18

u=18/-8

u=-2+1/4

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