2(u-5)-2=-2(-7u+3)-2u

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Solution for 2(u-5)-2=-2(-7u+3)-2u equation: 



2(u-5)-2=-2(-7u+3)-2u

We move all terms to the left:

2(u-5)-2-(-2(-7u+3)-2u)=0

We multiply parentheses

2u-(-2(-7u+3)-2u)-10-2=0



We calculate terms in parentheses: -(-2(-7u+3)-2u), so:

-2(-7u+3)-2u

We add all the numbers together, and all the variables

-2u-2(-7u+3)

We multiply parentheses

-2u+14u-6

We add all the numbers together, and all the variables

12u-6

Back to the equation:

-(12u-6)



We add all the numbers together, and all the variables

2u-(12u-6)-12=0

We get rid of parentheses

2u-12u+6-12=0

We add all the numbers together, and all the variables

-10u-6=0

We move all terms containing u to the left, all other terms to the right

-10u=6

u=6/-10

u=-3/5

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