2(u-5)-3=-3(-5u+1)-5u

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Solution for 2(u-5)-3=-3(-5u+1)-5u equation: 



2(u-5)-3=-3(-5u+1)-5u

We move all terms to the left:

2(u-5)-3-(-3(-5u+1)-5u)=0

We multiply parentheses

2u-(-3(-5u+1)-5u)-10-3=0



We calculate terms in parentheses: -(-3(-5u+1)-5u), so:

-3(-5u+1)-5u

We add all the numbers together, and all the variables

-5u-3(-5u+1)

We multiply parentheses

-5u+15u-3

We add all the numbers together, and all the variables

10u-3

Back to the equation:

-(10u-3)



We add all the numbers together, and all the variables

2u-(10u-3)-13=0

We get rid of parentheses

2u-10u+3-13=0

We add all the numbers together, and all the variables

-8u-10=0

We move all terms containing u to the left, all other terms to the right

-8u=10

u=10/-8

u=-1+1/4

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