2(u-5)-8=-5(-3u+4)-u

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Solution for 2(u-5)-8=-5(-3u+4)-u equation: 



2(u-5)-8=-5(-3u+4)-u

We move all terms to the left:

2(u-5)-8-(-5(-3u+4)-u)=0

We multiply parentheses

2u-(-5(-3u+4)-u)-10-8=0



We calculate terms in parentheses: -(-5(-3u+4)-u), so:

-5(-3u+4)-u

We add all the numbers together, and all the variables

-1u-5(-3u+4)

We multiply parentheses

-1u+15u-20

We add all the numbers together, and all the variables

14u-20

Back to the equation:

-(14u-20)



We add all the numbers together, and all the variables

2u-(14u-20)-18=0

We get rid of parentheses

2u-14u+20-18=0

We add all the numbers together, and all the variables

-12u+2=0

We move all terms containing u to the left, all other terms to the right

-12u=-2

u=-2/-12

u=1/6

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