2(u-5)=5u+2-3(-4u-2)

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Solution for 2(u-5)=5u+2-3(-4u-2) equation: 



2(u-5)=5u+2-3(-4u-2)

We move all terms to the left:

2(u-5)-(5u+2-3(-4u-2))=0

We multiply parentheses

2u-(5u+2-3(-4u-2))-10=0



We calculate terms in parentheses: -(5u+2-3(-4u-2)), so:

5u+2-3(-4u-2)

determiningTheFunctionDomain
5u-3(-4u-2)+2

We multiply parentheses

5u+12u+6+2

We add all the numbers together, and all the variables

17u+8

Back to the equation:

-(17u+8)



We get rid of parentheses

2u-17u-8-10=0

We add all the numbers together, and all the variables

-15u-18=0

We move all terms containing u to the left, all other terms to the right

-15u=18

u=18/-15

u=-1+1/5

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