2(u-6)-1=-3(-6u+2)-2u

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Solution for 2(u-6)-1=-3(-6u+2)-2u equation:



2(u-6)-1=-3(-6u+2)-2u
We move all terms to the left:
2(u-6)-1-(-3(-6u+2)-2u)=0
We multiply parentheses
2u-(-3(-6u+2)-2u)-12-1=0
We calculate terms in parentheses: -(-3(-6u+2)-2u), so:
-3(-6u+2)-2u
We add all the numbers together, and all the variables
-2u-3(-6u+2)
We multiply parentheses
-2u+18u-6
We add all the numbers together, and all the variables
16u-6
Back to the equation:
-(16u-6)
We add all the numbers together, and all the variables
2u-(16u-6)-13=0
We get rid of parentheses
2u-16u+6-13=0
We add all the numbers together, and all the variables
-14u-7=0
We move all terms containing u to the left, all other terms to the right
-14u=7
u=7/-14
u=-1/2

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