2(u-6)-9=-3(-9u+3)-9u

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Solution for 2(u-6)-9=-3(-9u+3)-9u equation: 



2(u-6)-9=-3(-9u+3)-9u

We move all terms to the left:

2(u-6)-9-(-3(-9u+3)-9u)=0

We multiply parentheses

2u-(-3(-9u+3)-9u)-12-9=0



We calculate terms in parentheses: -(-3(-9u+3)-9u), so:

-3(-9u+3)-9u

We add all the numbers together, and all the variables

-9u-3(-9u+3)

We multiply parentheses

-9u+27u-9

We add all the numbers together, and all the variables

18u-9

Back to the equation:

-(18u-9)



We add all the numbers together, and all the variables

2u-(18u-9)-21=0

We get rid of parentheses

2u-18u+9-21=0

We add all the numbers together, and all the variables

-16u-12=0

We move all terms containing u to the left, all other terms to the right

-16u=12

u=12/-16

u=-3/4

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