2(u-7)-3=-3(-6u+3)-6u

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Solution for 2(u-7)-3=-3(-6u+3)-6u equation: 



2(u-7)-3=-3(-6u+3)-6u

We move all terms to the left:

2(u-7)-3-(-3(-6u+3)-6u)=0

We multiply parentheses

2u-(-3(-6u+3)-6u)-14-3=0



We calculate terms in parentheses: -(-3(-6u+3)-6u), so:

-3(-6u+3)-6u

We add all the numbers together, and all the variables

-6u-3(-6u+3)

We multiply parentheses

-6u+18u-9

We add all the numbers together, and all the variables

12u-9

Back to the equation:

-(12u-9)



We add all the numbers together, and all the variables

2u-(12u-9)-17=0

We get rid of parentheses

2u-12u+9-17=0

We add all the numbers together, and all the variables

-10u-8=0

We move all terms containing u to the left, all other terms to the right

-10u=8

u=8/-10

u=-4/5

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