2(u-8)=4u=32

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Solution for 2(u-8)=4u=32 equation: 



2(u-8)=4u=32

We move all terms to the left:

2(u-8)-(4u)=0

We add all the numbers together, and all the variables

-4u+2(u-8)=0

We multiply parentheses

-4u+2u-16=0

We add all the numbers together, and all the variables

-2u-16=0

We move all terms containing u to the left, all other terms to the right

-2u=16

u=16/-2

u=-8

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