2(v+1)+4b=3(2v-1)+8

Solution for 2(v+1)+4b=3(2v-1)+8 equation:

Simplifying
2(v + 1) + 4b = 3(2v + -1) + 8

Reorder the terms:
2(1 + v) + 4b = 3(2v + -1) + 8
(1 * 2 + v * 2) + 4b = 3(2v + -1) + 8
(2 + 2v) + 4b = 3(2v + -1) + 8

Reorder the terms:
2 + 4b + 2v = 3(2v + -1) + 8

Reorder the terms:
2 + 4b + 2v = 3(-1 + 2v) + 8
2 + 4b + 2v = (-1 * 3 + 2v * 3) + 8
2 + 4b + 2v = (-3 + 6v) + 8

Reorder the terms:
2 + 4b + 2v = -3 + 8 + 6v

Combine like terms: -3 + 8 = 5
2 + 4b + 2v = 5 + 6v

Solving
2 + 4b + 2v = 5 + 6v

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + 4b + -2 + 2v = 5 + -2 + 6v

Reorder the terms:
2 + -2 + 4b + 2v = 5 + -2 + 6v

Combine like terms: 2 + -2 = 0
0 + 4b + 2v = 5 + -2 + 6v
4b + 2v = 5 + -2 + 6v

Combine like terms: 5 + -2 = 3
4b + 2v = 3 + 6v

Add '-2v' to each side of the equation.
4b + 2v + -2v = 3 + 6v + -2v

Combine like terms: 2v + -2v = 0
4b + 0 = 3 + 6v + -2v
4b = 3 + 6v + -2v

Combine like terms: 6v + -2v = 4v
4b = 3 + 4v

Divide each side by '4'.
b = 0.75 + v

Simplifying
b = 0.75 + v