2(v+1)+4v=3(2v+1)+8

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Solution for 2(v+1)+4v=3(2v+1)+8 equation: 



2(v+1)+4v=3(2v+1)+8

We move all terms to the left:

2(v+1)+4v-(3(2v+1)+8)=0

We add all the numbers together, and all the variables

4v+2(v+1)-(3(2v+1)+8)=0

We multiply parentheses

4v+2v-(3(2v+1)+8)+2=0



We calculate terms in parentheses: -(3(2v+1)+8), so:

3(2v+1)+8

We multiply parentheses

6v+3+8

We add all the numbers together, and all the variables

6v+11

Back to the equation:

-(6v+11)



We add all the numbers together, and all the variables

6v-(6v+11)+2=0

We get rid of parentheses

6v-6v-11+2=0

We add all the numbers together, and all the variables

-9!=0

There is no solution for this equation

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