2(v+1)+4v=3(2v+1)+8

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Solution for 2(v+1)+4v=3(2v+1)+8 equation:



2(v+1)+4v=3(2v+1)+8
We move all terms to the left:
2(v+1)+4v-(3(2v+1)+8)=0
We add all the numbers together, and all the variables
4v+2(v+1)-(3(2v+1)+8)=0
We multiply parentheses
4v+2v-(3(2v+1)+8)+2=0
We calculate terms in parentheses: -(3(2v+1)+8), so:
3(2v+1)+8
We multiply parentheses
6v+3+8
We add all the numbers together, and all the variables
6v+11
Back to the equation:
-(6v+11)
We add all the numbers together, and all the variables
6v-(6v+11)+2=0
We get rid of parentheses
6v-6v-11+2=0
We add all the numbers together, and all the variables
-9!=0
There is no solution for this equation

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