2(v+1)+4v=3(2v-1)+8

Solution for 2(v+1)+4v=3(2v-1)+8 equation:

Simplifying
2(v + 1) + 4v = 3(2v + -1) + 8

Reorder the terms:
2(1 + v) + 4v = 3(2v + -1) + 8
(1 * 2 + v * 2) + 4v = 3(2v + -1) + 8
(2 + 2v) + 4v = 3(2v + -1) + 8

Combine like terms: 2v + 4v = 6v
2 + 6v = 3(2v + -1) + 8

Reorder the terms:
2 + 6v = 3(-1 + 2v) + 8
2 + 6v = (-1 * 3 + 2v * 3) + 8
2 + 6v = (-3 + 6v) + 8

Reorder the terms:
2 + 6v = -3 + 8 + 6v

Combine like terms: -3 + 8 = 5
2 + 6v = 5 + 6v

Add '-6v' to each side of the equation.
2 + 6v + -6v = 5 + 6v + -6v

Combine like terms: 6v + -6v = 0
2 + 0 = 5 + 6v + -6v
2 = 5 + 6v + -6v

Combine like terms: 6v + -6v = 0
2 = 5 + 0
2 = 5

Solving
2 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.