2(v+1)+v4=3(2v-1)+8

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Solution for 2(v+1)+v4=3(2v-1)+8 equation: 



2(v+1)+v4=3(2v-1)+8

We move all terms to the left:

2(v+1)+v4-(3(2v-1)+8)=0

We add all the numbers together, and all the variables

v^4+2(v+1)-(3(2v-1)+8)=0

We multiply parentheses

v^4+2v-(3(2v-1)+8)+2=0



We calculate terms in parentheses: -(3(2v-1)+8), so:

3(2v-1)+8

We multiply parentheses

6v-3+8

We add all the numbers together, and all the variables

6v+5

Back to the equation:

-(6v+5)



We do not support evpression: v^4

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