2(v+1)=-2(6-7)+6v

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Solution for 2(v+1)=-2(6-7)+6v equation: 



2(v+1)=-2(6-7)+6v

We move all terms to the left:

2(v+1)-(-2(6-7)+6v)=0

We add all the numbers together, and all the variables

2(v+1)-(-2(-1)+6v)=0

We multiply parentheses

2v-(-2(-1)+6v)+2=0



We calculate terms in parentheses: -(-2(-1)+6v), so:

-2(-1)+6v

determiningTheFunctionDomain
6v-2(-1)

We add all the numbers together, and all the variables

6v+2

Back to the equation:

-(6v+2)



We get rid of parentheses

2v-6v-2+2=0

We add all the numbers together, and all the variables

-4v=0

v=0/-4

v=0

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