2(v+1)=-3(4v-4)+2v

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Solution for 2(v+1)=-3(4v-4)+2v equation: 



2(v+1)=-3(4v-4)+2v

We move all terms to the left:

2(v+1)-(-3(4v-4)+2v)=0

We multiply parentheses

2v-(-3(4v-4)+2v)+2=0



We calculate terms in parentheses: -(-3(4v-4)+2v), so:

-3(4v-4)+2v

We add all the numbers together, and all the variables

2v-3(4v-4)

We multiply parentheses

2v-12v+12

We add all the numbers together, and all the variables

-10v+12

Back to the equation:

-(-10v+12)



We get rid of parentheses

2v+10v-12+2=0

We add all the numbers together, and all the variables

12v-10=0

We move all terms containing v to the left, all other terms to the right

12v=10

v=10/12

v=5/6

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