2(v+1)=-4(4v-3)+4v

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Solution for 2(v+1)=-4(4v-3)+4v equation: 



2(v+1)=-4(4v-3)+4v

We move all terms to the left:

2(v+1)-(-4(4v-3)+4v)=0

We multiply parentheses

2v-(-4(4v-3)+4v)+2=0



We calculate terms in parentheses: -(-4(4v-3)+4v), so:

-4(4v-3)+4v

We add all the numbers together, and all the variables

4v-4(4v-3)

We multiply parentheses

4v-16v+12

We add all the numbers together, and all the variables

-12v+12

Back to the equation:

-(-12v+12)



We get rid of parentheses

2v+12v-12+2=0

We add all the numbers together, and all the variables

14v-10=0

We move all terms containing v to the left, all other terms to the right

14v=10

v=10/14

v=5/7

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