2(v+1)=5v-22

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Solution for 2(v+1)=5v-22 equation: 



2(v+1)=5v-22

We move all terms to the left:

2(v+1)-(5v-22)=0

We multiply parentheses

2v-(5v-22)+2=0

We get rid of parentheses

2v-5v+22+2=0

We add all the numbers together, and all the variables

-3v+24=0

We move all terms containing v to the left, all other terms to the right

-3v=-24

v=-24/-3

v=+8

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