2(v+2)+v=3(v+1)+6

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Solution for 2(v+2)+v=3(v+1)+6 equation: 



2(v+2)+v=3(v+1)+6

We move all terms to the left:

2(v+2)+v-(3(v+1)+6)=0

We add all the numbers together, and all the variables

v+2(v+2)-(3(v+1)+6)=0

We multiply parentheses

v+2v-(3(v+1)+6)+4=0



We calculate terms in parentheses: -(3(v+1)+6), so:

3(v+1)+6

We multiply parentheses

3v+3+6

We add all the numbers together, and all the variables

3v+9

Back to the equation:

-(3v+9)



We add all the numbers together, and all the variables

3v-(3v+9)+4=0

We get rid of parentheses

3v-3v-9+4=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

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