2(v+2)+v=3(v-1)+6

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Solution for 2(v+2)+v=3(v-1)+6 equation:


Simplifying
2(v + 2) + v = 3(v + -1) + 6

Reorder the terms:
2(2 + v) + v = 3(v + -1) + 6
(2 * 2 + v * 2) + v = 3(v + -1) + 6
(4 + 2v) + v = 3(v + -1) + 6

Combine like terms: 2v + v = 3v
4 + 3v = 3(v + -1) + 6

Reorder the terms:
4 + 3v = 3(-1 + v) + 6
4 + 3v = (-1 * 3 + v * 3) + 6
4 + 3v = (-3 + 3v) + 6

Reorder the terms:
4 + 3v = -3 + 6 + 3v

Combine like terms: -3 + 6 = 3
4 + 3v = 3 + 3v

Add '-3v' to each side of the equation.
4 + 3v + -3v = 3 + 3v + -3v

Combine like terms: 3v + -3v = 0
4 + 0 = 3 + 3v + -3v
4 = 3 + 3v + -3v

Combine like terms: 3v + -3v = 0
4 = 3 + 0
4 = 3

Solving
4 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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