2(v+2)-c=3(v-1)+9

Solution for 2(v+2)-c=3(v-1)+9 equation:

Simplifying
2(v + 2) + -1c = 3(v + -1) + 9

Reorder the terms:
2(2 + v) + -1c = 3(v + -1) + 9
(2 * 2 + v * 2) + -1c = 3(v + -1) + 9
(4 + 2v) + -1c = 3(v + -1) + 9

Reorder the terms:
4 + -1c + 2v = 3(v + -1) + 9

Reorder the terms:
4 + -1c + 2v = 3(-1 + v) + 9
4 + -1c + 2v = (-1 * 3 + v * 3) + 9
4 + -1c + 2v = (-3 + 3v) + 9

Reorder the terms:
4 + -1c + 2v = -3 + 9 + 3v

Combine like terms: -3 + 9 = 6
4 + -1c + 2v = 6 + 3v

Solving
4 + -1c + 2v = 6 + 3v

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -1c + -4 + 2v = 6 + -4 + 3v

Reorder the terms:
4 + -4 + -1c + 2v = 6 + -4 + 3v

Combine like terms: 4 + -4 = 0
0 + -1c + 2v = 6 + -4 + 3v
-1c + 2v = 6 + -4 + 3v

Combine like terms: 6 + -4 = 2
-1c + 2v = 2 + 3v

Add '-2v' to each side of the equation.
-1c + 2v + -2v = 2 + 3v + -2v

Combine like terms: 2v + -2v = 0
-1c + 0 = 2 + 3v + -2v
-1c = 2 + 3v + -2v

Combine like terms: 3v + -2v = 1v
-1c = 2 + 1v

Divide each side by '-1'.
c = -2 + -1v

Simplifying
c = -2 + -1v