2(v+2)-v=3(v+1)+9

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Solution for 2(v+2)-v=3(v+1)+9 equation: 



2(v+2)-v=3(v+1)+9

We move all terms to the left:

2(v+2)-v-(3(v+1)+9)=0

We add all the numbers together, and all the variables

-1v+2(v+2)-(3(v+1)+9)=0

We multiply parentheses

-1v+2v-(3(v+1)+9)+4=0



We calculate terms in parentheses: -(3(v+1)+9), so:

3(v+1)+9

We multiply parentheses

3v+3+9

We add all the numbers together, and all the variables

3v+12

Back to the equation:

-(3v+12)



We add all the numbers together, and all the variables

v-(3v+12)+4=0

We get rid of parentheses

v-3v-12+4=0

We add all the numbers together, and all the variables

-2v-8=0

We move all terms containing v to the left, all other terms to the right

-2v=8

v=8/-2

v=-4

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