2(v+2)-v=3(v-1)=9

Solution for 2(v+2)-v=3(v-1)=9 equation:

2(v+2)-v=3(v-1)=9

We move all terms to the left:

2(v+2)-v-(3(v-1))=0

We add all the numbers together, and all the variables

-1v+2(v+2)-(3(v-1))=0

We multiply parentheses

-1v+2v-(3(v-1))+4=0


We calculate terms in parentheses: -(3(v-1)), so:

3(v-1)

We multiply parentheses

3v-3

Back to the equation:

-(3v-3)


We add all the numbers together, and all the variables

v-(3v-3)+4=0

We get rid of parentheses

v-3v+3+4=0

We add all the numbers together, and all the variables

-2v+7=0

We move all terms containing v to the left, all other terms to the right

-2v=-7

v=-7/-2

v=3+1/2