2(v+2)=-4v-2

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Solution for 2(v+2)=-4v-2 equation: 



2(v+2)=-4v-2

We move all terms to the left:

2(v+2)-(-4v-2)=0

We multiply parentheses

2v-(-4v-2)+4=0

We get rid of parentheses

2v+4v+2+4=0

We add all the numbers together, and all the variables

6v+6=0

We move all terms containing v to the left, all other terms to the right

6v=-6

v=-6/6

v=-1

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