2(v+2)=5(v+3)

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Solution for 2(v+2)=5(v+3) equation: 



2(v+2)=5(v+3)

We move all terms to the left:

2(v+2)-(5(v+3))=0

We multiply parentheses

2v-(5(v+3))+4=0



We calculate terms in parentheses: -(5(v+3)), so:

5(v+3)

We multiply parentheses

5v+15

Back to the equation:

-(5v+15)



We get rid of parentheses

2v-5v-15+4=0

We add all the numbers together, and all the variables

-3v-11=0

We move all terms containing v to the left, all other terms to the right

-3v=11

v=11/-3

v=-3+2/3

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