2(v+2)=6v-12

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Solution for 2(v+2)=6v-12 equation: 



2(v+2)=6v-12

We move all terms to the left:

2(v+2)-(6v-12)=0

We multiply parentheses

2v-(6v-12)+4=0

We get rid of parentheses

2v-6v+12+4=0

We add all the numbers together, and all the variables

-4v+16=0

We move all terms containing v to the left, all other terms to the right

-4v=-16

v=-16/-4

v=+4

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