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2(v+3)-3v=-3(v-2)
We move all terms to the left:
2(v+3)-3v-(-3(v-2))=0
We add all the numbers together, and all the variables
-3v+2(v+3)-(-3(v-2))=0
We multiply parentheses
-3v+2v-(-3(v-2))+6=0
We calculate terms in parentheses: -(-3(v-2)), so:We add all the numbers together, and all the variables
-3(v-2)
We multiply parentheses
-3v+6
Back to the equation:
-(-3v+6)
-1v-(-3v+6)+6=0
We get rid of parentheses
-1v+3v-6+6=0
We add all the numbers together, and all the variables
2v=0
v=0/2
v=0
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