2(v+3)-3v=-3(v-2)

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Solution for 2(v+3)-3v=-3(v-2) equation: 



2(v+3)-3v=-3(v-2)

We move all terms to the left:

2(v+3)-3v-(-3(v-2))=0

We add all the numbers together, and all the variables

-3v+2(v+3)-(-3(v-2))=0

We multiply parentheses

-3v+2v-(-3(v-2))+6=0



We calculate terms in parentheses: -(-3(v-2)), so:

-3(v-2)

We multiply parentheses

-3v+6

Back to the equation:

-(-3v+6)



We add all the numbers together, and all the variables

-1v-(-3v+6)+6=0

We get rid of parentheses

-1v+3v-6+6=0

We add all the numbers together, and all the variables

2v=0

v=0/2

v=0

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