2(v+3)=-2(6v-1)+2v

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Solution for 2(v+3)=-2(6v-1)+2v equation: 



2(v+3)=-2(6v-1)+2v

We move all terms to the left:

2(v+3)-(-2(6v-1)+2v)=0

We multiply parentheses

2v-(-2(6v-1)+2v)+6=0



We calculate terms in parentheses: -(-2(6v-1)+2v), so:

-2(6v-1)+2v

We add all the numbers together, and all the variables

2v-2(6v-1)

We multiply parentheses

2v-12v+2

We add all the numbers together, and all the variables

-10v+2

Back to the equation:

-(-10v+2)



We get rid of parentheses

2v+10v-2+6=0

We add all the numbers together, and all the variables

12v+4=0

We move all terms containing v to the left, all other terms to the right

12v=-4

v=-4/12

v=-1/3

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