2(v+3)=-2(8v-2)+2v

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Solution for 2(v+3)=-2(8v-2)+2v equation: 



2(v+3)=-2(8v-2)+2v

We move all terms to the left:

2(v+3)-(-2(8v-2)+2v)=0

We multiply parentheses

2v-(-2(8v-2)+2v)+6=0



We calculate terms in parentheses: -(-2(8v-2)+2v), so:

-2(8v-2)+2v

We add all the numbers together, and all the variables

2v-2(8v-2)

We multiply parentheses

2v-16v+4

We add all the numbers together, and all the variables

-14v+4

Back to the equation:

-(-14v+4)



We get rid of parentheses

2v+14v-4+6=0

We add all the numbers together, and all the variables

16v+2=0

We move all terms containing v to the left, all other terms to the right

16v=-2

v=-2/16

v=-1/8

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