2(v+4)-5v=35

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Solution for 2(v+4)-5v=35 equation: 



2(v+4)-5v=35

We move all terms to the left:

2(v+4)-5v-(35)=0

We add all the numbers together, and all the variables

-5v+2(v+4)-35=0

We multiply parentheses

-5v+2v+8-35=0

We add all the numbers together, and all the variables

-3v-27=0

We move all terms containing v to the left, all other terms to the right

-3v=27

v=27/-3

v=-9

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