2(v+4)=-4(3v-1)+4v

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Solution for 2(v+4)=-4(3v-1)+4v equation:



2(v+4)=-4(3v-1)+4v
We move all terms to the left:
2(v+4)-(-4(3v-1)+4v)=0
We multiply parentheses
2v-(-4(3v-1)+4v)+8=0
We calculate terms in parentheses: -(-4(3v-1)+4v), so:
-4(3v-1)+4v
We add all the numbers together, and all the variables
4v-4(3v-1)
We multiply parentheses
4v-12v+4
We add all the numbers together, and all the variables
-8v+4
Back to the equation:
-(-8v+4)
We get rid of parentheses
2v+8v-4+8=0
We add all the numbers together, and all the variables
10v+4=0
We move all terms containing v to the left, all other terms to the right
10v=-4
v=-4/10
v=-2/5

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