2(v+4)=4v-2

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Solution for 2(v+4)=4v-2 equation: 



2(v+4)=4v-2

We move all terms to the left:

2(v+4)-(4v-2)=0

We multiply parentheses

2v-(4v-2)+8=0

We get rid of parentheses

2v-4v+2+8=0

We add all the numbers together, and all the variables

-2v+10=0

We move all terms containing v to the left, all other terms to the right

-2v=-10

v=-10/-2

v=+5

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