2(v+5)=-6(2v-2)+4v

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Solution for 2(v+5)=-6(2v-2)+4v equation: 



2(v+5)=-6(2v-2)+4v

We move all terms to the left:

2(v+5)-(-6(2v-2)+4v)=0

We multiply parentheses

2v-(-6(2v-2)+4v)+10=0



We calculate terms in parentheses: -(-6(2v-2)+4v), so:

-6(2v-2)+4v

We add all the numbers together, and all the variables

4v-6(2v-2)

We multiply parentheses

4v-12v+12

We add all the numbers together, and all the variables

-8v+12

Back to the equation:

-(-8v+12)



We get rid of parentheses

2v+8v-12+10=0

We add all the numbers together, and all the variables

10v-2=0

We move all terms containing v to the left, all other terms to the right

10v=2

v=2/10

v=1/5

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