2(v+9)=-2v+22

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Solution for 2(v+9)=-2v+22 equation: 



2(v+9)=-2v+22

We move all terms to the left:

2(v+9)-(-2v+22)=0

We multiply parentheses

2v-(-2v+22)+18=0

We get rid of parentheses

2v+2v-22+18=0

We add all the numbers together, and all the variables

4v-4=0

We move all terms containing v to the left, all other terms to the right

4v=4

v=4/4

v=1

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