2(v+9)=-5(5v-2)+9v

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Solution for 2(v+9)=-5(5v-2)+9v equation: 



2(v+9)=-5(5v-2)+9v

We move all terms to the left:

2(v+9)-(-5(5v-2)+9v)=0

We multiply parentheses

2v-(-5(5v-2)+9v)+18=0



We calculate terms in parentheses: -(-5(5v-2)+9v), so:

-5(5v-2)+9v

We add all the numbers together, and all the variables

9v-5(5v-2)

We multiply parentheses

9v-25v+10

We add all the numbers together, and all the variables

-16v+10

Back to the equation:

-(-16v+10)



We get rid of parentheses

2v+16v-10+18=0

We add all the numbers together, and all the variables

18v+8=0

We move all terms containing v to the left, all other terms to the right

18v=-8

v=-8/18

v=-4/9

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