2(v-1)+7=3(v-2)+2v

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Solution for 2(v-1)+7=3(v-2)+2v equation: 



2(v-1)+7=3(v-2)+2v

We move all terms to the left:

2(v-1)+7-(3(v-2)+2v)=0

We multiply parentheses

2v-(3(v-2)+2v)-2+7=0



We calculate terms in parentheses: -(3(v-2)+2v), so:

3(v-2)+2v

We add all the numbers together, and all the variables

2v+3(v-2)

We multiply parentheses

2v+3v-6

We add all the numbers together, and all the variables

5v-6

Back to the equation:

-(5v-6)



We add all the numbers together, and all the variables

2v-(5v-6)+5=0

We get rid of parentheses

2v-5v+6+5=0

We add all the numbers together, and all the variables

-3v+11=0

We move all terms containing v to the left, all other terms to the right

-3v=-11

v=-11/-3

v=3+2/3

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