2(v-1)=8v+6-2(-3v-4)

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Solution for 2(v-1)=8v+6-2(-3v-4) equation: 



2(v-1)=8v+6-2(-3v-4)

We move all terms to the left:

2(v-1)-(8v+6-2(-3v-4))=0

We multiply parentheses

2v-(8v+6-2(-3v-4))-2=0



We calculate terms in parentheses: -(8v+6-2(-3v-4)), so:

8v+6-2(-3v-4)

determiningTheFunctionDomain
8v-2(-3v-4)+6

We multiply parentheses

8v+6v+8+6

We add all the numbers together, and all the variables

14v+14

Back to the equation:

-(14v+14)



We get rid of parentheses

2v-14v-14-2=0

We add all the numbers together, and all the variables

-12v-16=0

We move all terms containing v to the left, all other terms to the right

-12v=16

v=16/-12

v=-1+1/3

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