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2(v-10)=4(3v+2)
We move all terms to the left:
2(v-10)-(4(3v+2))=0
We multiply parentheses
2v-(4(3v+2))-20=0
We calculate terms in parentheses: -(4(3v+2)), so:We get rid of parentheses
4(3v+2)
We multiply parentheses
12v+8
Back to the equation:
-(12v+8)
2v-12v-8-20=0
We add all the numbers together, and all the variables
-10v-28=0
We move all terms containing v to the left, all other terms to the right
-10v=28
v=28/-10
v=-2+4/5
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