2(v-2)-v=3(v-1)+9

Solution for 2(v-2)-v=3(v-1)+9 equation:

2(v-2)-v=3(v-1)+9

We move all terms to the left:

2(v-2)-v-(3(v-1)+9)=0

We add all the numbers together, and all the variables

-1v+2(v-2)-(3(v-1)+9)=0

We multiply parentheses

-1v+2v-(3(v-1)+9)-4=0


We calculate terms in parentheses: -(3(v-1)+9), so:

3(v-1)+9

We multiply parentheses

3v-3+9

We add all the numbers together, and all the variables

3v+6

Back to the equation:

-(3v+6)


We add all the numbers together, and all the variables

v-(3v+6)-4=0

We get rid of parentheses

v-3v-6-4=0

We add all the numbers together, and all the variables

-2v-10=0

We move all terms containing v to the left, all other terms to the right

-2v=10

v=10/-2

v=-5