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2(v-2)=2v+3-2(-9v-4)
We move all terms to the left:
2(v-2)-(2v+3-2(-9v-4))=0
We multiply parentheses
2v-(2v+3-2(-9v-4))-4=0
We calculate terms in parentheses: -(2v+3-2(-9v-4)), so:We get rid of parentheses
2v+3-2(-9v-4)
determiningTheFunctionDomain 2v-2(-9v-4)+3
We multiply parentheses
2v+18v+8+3
We add all the numbers together, and all the variables
20v+11
Back to the equation:
-(20v+11)
2v-20v-11-4=0
We add all the numbers together, and all the variables
-18v-15=0
We move all terms containing v to the left, all other terms to the right
-18v=15
v=15/-18
v=-5/6
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