2(v-2)=2v+8-2(-9v-2)

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Solution for 2(v-2)=2v+8-2(-9v-2) equation: 



2(v-2)=2v+8-2(-9v-2)

We move all terms to the left:

2(v-2)-(2v+8-2(-9v-2))=0

We multiply parentheses

2v-(2v+8-2(-9v-2))-4=0



We calculate terms in parentheses: -(2v+8-2(-9v-2)), so:

2v+8-2(-9v-2)

determiningTheFunctionDomain
2v-2(-9v-2)+8

We multiply parentheses

2v+18v+4+8

We add all the numbers together, and all the variables

20v+12

Back to the equation:

-(20v+12)



We get rid of parentheses

2v-20v-12-4=0

We add all the numbers together, and all the variables

-18v-16=0

We move all terms containing v to the left, all other terms to the right

-18v=16

v=16/-18

v=-8/9

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