2(v-2)=5v+9-3(-5v-1)

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Solution for 2(v-2)=5v+9-3(-5v-1) equation: 



2(v-2)=5v+9-3(-5v-1)

We move all terms to the left:

2(v-2)-(5v+9-3(-5v-1))=0

We multiply parentheses

2v-(5v+9-3(-5v-1))-4=0



We calculate terms in parentheses: -(5v+9-3(-5v-1)), so:

5v+9-3(-5v-1)

determiningTheFunctionDomain
5v-3(-5v-1)+9

We multiply parentheses

5v+15v+3+9

We add all the numbers together, and all the variables

20v+12

Back to the equation:

-(20v+12)



We get rid of parentheses

2v-20v-12-4=0

We add all the numbers together, and all the variables

-18v-16=0

We move all terms containing v to the left, all other terms to the right

-18v=16

v=16/-18

v=-8/9

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