2(v-3)-3=-3(-9v+5)-9v

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Solution for 2(v-3)-3=-3(-9v+5)-9v equation: 



2(v-3)-3=-3(-9v+5)-9v

We move all terms to the left:

2(v-3)-3-(-3(-9v+5)-9v)=0

We multiply parentheses

2v-(-3(-9v+5)-9v)-6-3=0



We calculate terms in parentheses: -(-3(-9v+5)-9v), so:

-3(-9v+5)-9v

We add all the numbers together, and all the variables

-9v-3(-9v+5)

We multiply parentheses

-9v+27v-15

We add all the numbers together, and all the variables

18v-15

Back to the equation:

-(18v-15)



We add all the numbers together, and all the variables

2v-(18v-15)-9=0

We get rid of parentheses

2v-18v+15-9=0

We add all the numbers together, and all the variables

-16v+6=0

We move all terms containing v to the left, all other terms to the right

-16v=-6

v=-6/-16

v=3/8

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