2(v-3)-3=-6(4v+1)-7v

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Solution for 2(v-3)-3=-6(4v+1)-7v equation: 



2(v-3)-3=-6(4v+1)-7v

We move all terms to the left:

2(v-3)-3-(-6(4v+1)-7v)=0

We multiply parentheses

2v-(-6(4v+1)-7v)-6-3=0



We calculate terms in parentheses: -(-6(4v+1)-7v), so:

-6(4v+1)-7v

We add all the numbers together, and all the variables

-7v-6(4v+1)

We multiply parentheses

-7v-24v-6

We add all the numbers together, and all the variables

-31v-6

Back to the equation:

-(-31v-6)



We add all the numbers together, and all the variables

2v-(-31v-6)-9=0

We get rid of parentheses

2v+31v+6-9=0

We add all the numbers together, and all the variables

33v-3=0

We move all terms containing v to the left, all other terms to the right

33v=3

v=3/33

v=1/11

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